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Let \(X\) and \(Y\) have a bivariate normal distribution with parameters \(\mu_{1}=\) \(\mu_{2}=0, \sigma_{1}^{2}=\sigma_{2}^{2}=1\), and correlation coefficient \(\rho .\) Find the distribution of the random variable \(Z=a X+b Y\) in which \(a\) and \(b\) are nonzero constants.

Short Answer

Expert verified
The random variable \(Z\) = \(aX+bY\) is normally distributed with parameters \(N(0, a^2+b^2+2ab\rho)\).

Step by step solution

01

Define the random variable \(Z\)

First, let's define the random variable \(Z\). We are given \(Z=aX+bY\). This implicates that \(Z\) is a normal random variable because a linear combination of normal random variables is also normal (if \(X\) and \(Y\) are jointly normal). The challenge is to find the parameters of this normal distribution namely its mean and variance.
02

Find the expected value and variance of \(Z\)

From the properties of expectation and variance, the expected value of \(Z\) can be expressed as \[E[Z] = E[aX+bY] = aE[X] + bE[Y] = a\mu_1 + b\mu_2 = 0.\] The variance of \(Z\) can be obtained as: \[Var(Z) = Var(aX+bY) = a^2Var(X) + b^2Var(Y) + 2abCov(X,Y),\] where \(Cov(X,Y)\) is given by \(\rho\sigma_1\sigma_2\). Substituting the given values, we will have \(Var(Z) = a^2 + b^2 + 2ab\rho\).
03

Express the distribution of \(Z\)

Now we know that \(Z\) is a normal random variable with mean 0 and variance \(a^2 + b^2 + 2ab\rho\), we can say \(Z\) follows a normal distribution \(N(0, a^2 + b^2 + 2ab\rho)\). This is the distribution of the random variable \(Z\)=\(aX+bY\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Combination of Random Variables
In the context of probability and statistics, the term linear combination of random variables refers to an expression constructed from a set of random variables by multiplying each with a constant and then adding the results. This operation is fundamental to understanding many processes in statistics, such as regression analysis, and in the study we're looking at, the linear combination defines the new random variable, denoted as \( Z = aX + bY \).

One important property to remember is that if random variables \(X\) and \(Y\) are separately normal and are part of a bivariate normal distribution, as stated in the exercise, the linear combination \(Z\) will also follow a normal distribution. These relationships make the analysis and prediction of complex variables possible, facilitating the understanding of diverse phenomena in various scientific fields, from finance to engineering.
Expected Value and Variance
Understanding expected value and variance is critical in the realm of probability theory as they measure the central tendency and the dispersion of a probability distribution, respectively. The expected value, or the mean, of a random variable provides a measure of the 'center' of its distribution. In simpler terms, it tells us the average outcome we can expect if we were to repeat an experiment many times.

The variance, on the other hand, gives us an idea of how spread out the values of the random variable are around the mean. In terms of calculations, for a given linear combination of variables \(Z = aX + bY\), the expected value is \(E[Z] = a\text{E}[X] + b\text{E}[Y]\), and the variance is a bit more complex: \(Var(Z) = a^2Var(X) + b^2Var(Y) + 2abCov(X,Y)\), incorporating the idea of covariance, which measures how much two random variables change together. A clear and practical understanding of these concepts is vital for students and professionals alike to correctly interpret data and make informed decisions.
Normal Random Variable
The normal random variable is a cornerstone in the study of probability and statistics due to its prevalence in the natural and social sciences. A normal random variable has a distribution that is symmetric about the mean, indicating that data near the mean are more frequent in occurrence than data far from the mean.

When a random variable is described as normal, it follows the well-known bell-shaped curve, characterized entirely by its mean \( \text{E}[X] \) and its variance \( Var(X) \). The centrality of the normal distribution can be attributed to the Central Limit Theorem, which tells us that under certain conditions, the sum (or average) of a large number of independent random variables will be approximately normal, regardless of their underlying distributions. This property of normal random variables makes them invaluable for statistical modeling and hypothesis testing where predictions and inferences about populations from samples are made.

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Most popular questions from this chapter

Suppose \(\mathbf{X}\) is distributed \(N_{n}(\boldsymbol{\mu}, \mathbf{\Sigma}) .\) Let \(\bar{X}=n^{-1} \sum_{i=1}^{n} X_{i}\). (a) Write \(\bar{X}\) as aX for an appropriate vector a and apply Theorem \(3.5 .2\) to find the distribution of \(\bar{X}\). (b) Determine the distribution of \(\bar{X}\) if all of its component random variables \(X_{i}\) have the same mean \(\mu\).

Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie of this type contains at least two chocolate chips to be greater than \(0.99 .\) Find the smallest value of the mean that the distribution can take.

If the random variable \(X\) has a Poisson distribution such that \(P(X=1)=\) \(P(X=2)\), find \(P(X=4)\).

Let \(X\) have a Poisson distribution. If \(P(X=1)=P(X=3)\), find the mode of the distribution.

Consider a shipment of 1000 items into a factory. Suppose the factory can tolerate about \(5 \%\) defective items. Let \(X\) be the number of defective items in a sample without replacement of size \(n=10 .\) Suppose the factory returns the shipment if \(X \geq 2\). (a) Obtain the probability that the factory returns a shipment of items that has \(5 \%\) defective items. (b) Suppose the shipment has \(10 \%\) defective items. Obtain the probability that the factory returns such a shipment. (c) Obtain approximations to the probabilities in parts (a) and (b) using appropriate binomial distributions. Note: If you do not have access to a computer package with a hypergeometric command, obtain the answer to (c) only. This is what would have been done in practice 20 years ago. If you have access to \(\mathrm{R}\), then the command dhyper \((\mathrm{x}, \mathrm{D}, \mathrm{N}-\mathrm{D}, \mathrm{n})\) returns the probability in expression (3.1.7).

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