Chapter 3: Problem 10
The approximation discussed in Exercise \(3.2 .8\) can be made precise in the following way. Suppose \(X_{n}\) is binomial with the parameters \(n\) and \(p=\lambda / n\), for a given \(\lambda>0 .\) Let \(Y\) be Poisson with mean \(\lambda\). Show that \(P\left(X_{n}=k\right) \rightarrow P(Y=k)\), as \(n \rightarrow \infty\), for an arbitrary but fixed value of \(k\). Hint: First show that: $$ P\left(X_{n}=k\right)=\frac{\lambda^{k}}{k !}\left[\frac{n(n-1) \cdots(n-k+1)}{n^{k}}\left(1-\frac{\lambda}{n}\right)^{-k}\right]\left(1-\frac{\lambda}{n}\right)^{n} $$
Short Answer
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