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Show that Kendall's \(\tau\) satisfies the inequality \(-1 \leq \tau \leq 1\).

Short Answer

Expert verified
Kendall's tau, being a measure of correlation, lies between -1 and 1. This is derived from its formula and the definition of concordant and discordant pairs. The value of \(\tau\) is 1 when all pairs are concordant and -1 when all are discordant, proving \(-1 \leq \tau \leq 1\).

Step by step solution

01

Understand Kendall's Tau

Kendall's Tau is a measure of correlation between two ranked variables. It's named after Maurice Kendall who introduced it in 1938. The formula for computing this correlation coefficient is: \[\tau = \frac{(\text{number of concordant pairs}) - (\text{number of discordant pairs})}{0.5 \cdot n \cdot (n-1)}\]where 'n' is the total number of observations. Concordant pairs are those pairs in which the ranking of both variables increase or decrease together. Meanwhile, discordant pairs are those pairs in which the ranking of one variable increases while the ranking of the other variable decreases.
02

Deriving the Range of Kendall's Tau

It can be observed from the formula that the maximum number of either concordant or discordant pairs can be \(0.5 \cdot n \cdot (n-1)\). Therefore, in the worst-case scenario, all the pairs are either concordant or discordant, making the value of \( \tau \) either -1 or 1, respectively.
03

Proof of Kendall's Tau Range

Therefore, as seen, in the best-case scenario, there are no discordant pairs (all pairs are concordant), which leads to Kendall's \( \tau = 1 \). Conversely, in the worst-case scenario, all pairs are discordant (no pairs are concordant), which leads to Kendall's \( \tau = -1 \). Given these two bounds, and all possible combinations of concordant and discordant pairs, we have demonstrated that Kendall's tau always lies within the range \(-1 \leq \tau \leq 1\). This completes the proof of the Kendall tau range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation Coefficient
The correlation coefficient is a statistical measure that calculates the strength, direction, and relationship between two variables. In the context of Kendall's Tau, it specifically addresses the correlation between two ranked variables. To grasp this concept, think of two lists of rankings, such as sports teams in a league or the popularity of products. If a high rank in one list tends to be associated with a high (or low) rank in the other list, then there is a strong correlation. The coefficient ranges from -1 to +1.

A value of +1 indicates a perfect positive correlation, meaning as one variable increases, so does the other. Conversely, a -1 indicates a perfect negative correlation, showing that as one variable increases, the other decreases. A value of 0 signifies no correlation; the variables do not affect each other. Kendall's Tau is unique as it's a non-parametric measure, meaning it does not assume a normal distribution of the variables, making it useful for ordinal data where the assumption of normality cannot be made.
Concordant and Discordant Pairs
In the evaluation of Kendall's Tau, the concepts of concordant and discordant pairs are paramount. Concordant pairs occur when the order of the rankings for two pairs is consistent. For instance, if one food item is both less expensive and more nutritious than another, these two items form a concordant pair. On the other hand, discordant pairs are exactly the opposite; if one item is less expensive but less nutritious when compared to another, they form a discordant pair.

For practical application, imagine you've ranked your top five movies. If a friend has a similar ranking, most pairs of movies you compare will be concordant. Kendall's Tau quantifies how often this concordance occurs across all pairs. The balance between concordant and discordant pairs—where one set does not greatly outnumber the other—leads to a Tau value close to 0, indicating a weak or nonexistent relationship between the variables under study.
Non-parametric Statistics
Non-parametric statistics refer to a branch of statistics that is not reliant on data belonging to any particular probability distribution. These methods are particularly useful when dealing with ordinal data or when the assumptions necessary for parametric tests (like normal distribution) are violated.

Kendall's Tau is an example of a non-parametric statistical measure because it does not require the assumption of normality of the data. It depends solely on the ranks of the data points, not their actual values. This attribute makes it highly versatile and robust for real-world data, which is often not perfectly normally distributed. Non-parametric methods like Kendall's Tau are valuable tools because they can be applied more broadly and with fewer assumptions about the data, which is especially important in fields like social sciences and market research where data often defy parametric norms.

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Most popular questions from this chapter

In this section, as discussed above expression \((10.5 .2)\), the scores \(a_{\varphi}(i)\) are generated by the standardized score function \(\varphi(u) ;\) that is, \(\int_{0}^{1} \varphi(u) d u=0\) and \(\int_{0}^{1} \varphi^{2}(u) d u=1\). Suppose that \(\psi(u)\) is a square-integrable function defined on the interval \((0,1)\). Consider the score function defined by $$ \varphi(u)=\frac{\psi(u)-\bar{\psi}}{\int_{0}^{1}[\psi(v)-\bar{\psi}]^{2} d v}, $$ where \(\bar{\psi}=\int_{0}^{1} \psi(v) d v\). Show that \(\varphi(u)\) is a standardized score function.

In Exercise \(10.9 .5\), the influence function of the variance functional was derived directly. Assuming that the mean of \(X\) is 0 , note that the variance functional, \(V\left(F_{X}\right)\), also solves the equation $$ 0=\int_{-\infty}^{\infty}\left[t^{2}-V\left(F_{X}\right)\right] f_{X}(t) d t $$ (a) Determine the natural estimator of the variance by writing the defining equation at the empirical cdf \(F_{n}(t)\), for \(X_{1}-\bar{X}, \ldots, X_{n}-\bar{X}\) iid with \(\operatorname{cdf} F_{X}(t)\) and solving for \(V\left(F_{n}\right)\). (b) As in Exercise \(10.9 .6\), write the defining equation for the variance functional at the contaminated \(\operatorname{cdf} F_{x, \epsilon}(t)\). (c) Then derive the influence function by implicit differentiation of the defining equation in part (b).

Optimal signed-rank based methods also exist for the one-sample problem. In this exercise, we briefly discuss these methods. Let \(X_{1}, X_{2}, \ldots, X_{n}\) follow the location model $$ X_{i}=\theta+e_{i}, \quad(10.5 .39) $$ where \(e_{1}, e_{2}, \ldots, e_{n}\) are iid with pdf \(f(x)\), which is symmetric about \(0 ;\) i.e., \(f(-x)=\) \(f(x)\) (a) Show that under symmetry the optimal two-sample score function \((10.5 .26)\) satisfies $$ \varphi_{f}(1-u)=-\varphi_{f}(u), \quad 00 $$ Our decision rule for the statistic \(W_{\varphi^{+}}\) is to reject \(H_{0}\) in favor of \(H_{1}\) if \(W_{\varphi^{+}} \geq\) \(k\), for some \(k\). Write \(W_{\varphi^{+}}\) in terms of the anti-ranks, \((10.3 .5) .\) Show that \(W_{\varphi^{+}}\) is distribution-free under \(H_{0}\). (f) Determine the mean and variance of \(W_{\varphi^{+}}\) under \(H_{0}\). (g) Assuming that, when properly standardized, the null distribution is asymptotically normal, determine the asymptotic test.

Suppose the random variable \(e\) has cdf \(F(t)\). Let \(\varphi(u)=\sqrt{12}[u-(1 / 2)]\), \(0

Let \(X\) be a continuous random variable with pdf \(f(x)\). Suppose \(f(x)\) is symmetric about \(a\); i.e., \(f(x-a)=f(-(x-a))\). Show that the random variables \(X-a\) and \(-(X-a)\) have the same pdf.

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