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Let \(X\) have the pdf \(f(x)=3 x^{2}, 0

Short Answer

Expert verified
The expected value of the area of the rectangle is \(\frac{3}{20}\).

Step by step solution

01

Understanding the required expectation

The area of the rectangle is given by \(X*(1-X)\) as the sides of the rectangle are \(X\) and \(1-X\). Therefore, the expectation that we are looking for is \(\int_{0}^{1}X*(1-X)*3x^{2}dx\).
02

Performing the Integral

Performing the integral we get: \(E[X*(1-X)] = \int_{0}^{1}X*(1-X)*3x^{2}dx = \int_{0}^{1}(3x^{3} - 3x^{4})dx = [\frac{3}{4}x^{4} - \frac{3}{5}x^{5}]_{0}^{1}\).
03

Evaluating the Definite Integral

By substituting the limits of the integral, the result of the integral becomes: \([\frac{3}{4} - \frac{3}{5}] - [0] = \frac{3}{4} - \frac{3}{5} = \frac{3}{20}\).

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