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Let \(X_{1}\) and \(X_{2}\) be two independent random variables so that the variances of \(X_{1}\) and \(X_{2}\) are \(\sigma_{1}^{2}=k\) and \(\sigma_{2}^{2}=2\), respectively. Given that the variance of \(Y=3 X_{2}-X_{1}\) is 25, find \(k\)

Short Answer

Expert verified
The value of \(k\) is 7.

Step by step solution

01

Understand the variance equations

The variance of the sum or difference of two independent random variables is equal to the sum of their variances. Hence, for our random variables \(X_{1}\) and \(X_{2}\), the variance of \(Y=3X_{2}-X_{1}\) can be calculated as \(Var(Y)=Var(3X_{2}-X_{1})=Var(3X_{2})+Var(-X_{1})=(3^2)Var(X_{2})+(-1^2)Var(X_{1})\).
02

Substitute known values

We substitute the given values into the equation from Step 1. As established, \(Var(Y)=25\), \(Var(X_{2})=2\), and \(Var(X_{1})=\sigma_{1}^{2}=k\). Hence 25 = 9*2 + k.
03

Solve for k

To find the value of k, we simplify the equation 25=9*2+k to get \(k=25-18\).

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