Chapter 11: Problem 9
. Let \(Y_{4}\) be the largest order statistic of a sanple of size \(n=4\) from a
distribution with uniform pdf \(f(x ; \theta)=1 / \theta, 0
Short Answer
Expert verified
The Bayesian estimator for \(\theta\) given \(Y_4\) and the loss function \(|\delta(Y_4) - \theta|\) is \(\delta(Y_4) = 2Y_{4}\).
Step by step solution
01
Form the posterior distribution
Bayesian analysis starts with a prior distribution and then updates this with the likelihood function to form the posterior distribution. Our prior for this problem is \(g(\theta)=2 / \theta^{3}, 1<\theta<\infty\), and the likelihood function is \(f(x ; \theta)=1 / \theta, 0<x<\theta\). Therefore, the posterior distribution is proportional to the product of the prior and the likelihood: \(p(\theta|Y_{4}) \propto g(\theta)f(Y_{4}; \theta) = (2 / \theta^{3})*(1 / \theta) = 2 / \theta^{4}\).
02
Normalize the posterior distribution
For the posterior distribution to be a true probability distribution, it must integrate (sum) to 1. We need to find the normalization constant, say C, such that \(\int_{1}^{\infty}C * p(\theta|Y_{4})d\theta=1\). Computing this integral we get \(C = 1 / Y_{4}\). Thus, the normalized posterior distribution is \(p(\theta|Y_{4}) = 2 / (\theta^{4} * Y_{4})\).
03
Derive the Bayesian estimator
In Bayesian analysis, the estimator is the value that minimizes the expected loss. In this case, the loss function is absolute error loss, given by \(L(\theta, \delta) = |\delta - \theta|\). By taking the derivative of this loss function with respect to \(\delta\) and setting it to zero, we find that the Bayesian estimator is the median of the posterior distribution. It turns out the Bayesian estimator for this problem, given this loss function, is \(\delta(Y_{4}) = 2Y_{4}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Order Statistic
The largest order statistic from a sample refers to the maximum value within that sample. In our exercise, we consider a sample of size 4 from a uniform distribution. This order statistic is denoted as \(Y_4\), representing the largest observed value among four draws from the same distribution.
Order statistics are crucial in statistics as they help identify extremes like minimum, maximum, and various percentiles of a dataset. In a Bayesian context, they provide valuable information for estimating unknown parameters, such as \(\theta\) in our case. Knowing \(Y_4\) allows us to better understand which values of \(\theta\) are more plausible, given the observed data.
Order statistics are crucial in statistics as they help identify extremes like minimum, maximum, and various percentiles of a dataset. In a Bayesian context, they provide valuable information for estimating unknown parameters, such as \(\theta\) in our case. Knowing \(Y_4\) allows us to better understand which values of \(\theta\) are more plausible, given the observed data.
Uniform Distribution
A uniform distribution is a probability distribution where every outcome in the range is equally likely. For this exercise, our uniform distribution is defined such that the probability density function (pdf) is \(f(x; \theta) = 1/\theta\) for \(0 < x < \theta\), and zero elsewhere. This means any value between 0 and \(\theta\) is just as likely as any other value within this range.
Uniform distributions are simple yet powerful tools in statistics, representing randomness without favoring any outcome within the specified bounds. They serve as a foundation for more complex probabilistic models and analyses, such as the one we're dealing with in forming the posterior distribution.
Uniform distributions are simple yet powerful tools in statistics, representing randomness without favoring any outcome within the specified bounds. They serve as a foundation for more complex probabilistic models and analyses, such as the one we're dealing with in forming the posterior distribution.
Posterior Distribution
The posterior distribution reflects our updated knowledge about a parameter after considering new evidence or data. This update is based on Bayes' theorem, a cornerstone of Bayesian statistics. Our problem involves determining the posterior distribution of \(\theta\) given \(Y_4\).
- The prior distribution here is \(g(\theta) = 2/\theta^3\) for \(1 < \theta < \infty\).
- The likelihood function is based on the uniform distribution, given as \(f(Y_4; \theta) = 1/\theta\).
Absolute Error Loss
Absolute error loss is a simple yet effective way to measure the accuracy of an estimator. This loss function is defined as \(L(\theta, \delta) = |\delta - \theta|\), highlighting the absolute difference between our estimate \(\delta\) and the true parameter \(\theta\).
In Bayesian estimation, this loss function helps determine the best estimate by seeking the value of \(\delta\) that minimizes the expected error. Often, this leads us to choosing the median of the posterior distribution as the most accurate estimator under absolute error loss. This aligns with our exercise, where the Bayesian estimator for \(\theta\) given \(Y_4\) is \(\delta(Y_4) = 2Y_4\). This approach ensures that we do not heavily penalize outlying errors and instead find a central, balanced estimate.
In Bayesian estimation, this loss function helps determine the best estimate by seeking the value of \(\delta\) that minimizes the expected error. Often, this leads us to choosing the median of the posterior distribution as the most accurate estimator under absolute error loss. This aligns with our exercise, where the Bayesian estimator for \(\theta\) given \(Y_4\) is \(\delta(Y_4) = 2Y_4\). This approach ensures that we do not heavily penalize outlying errors and instead find a central, balanced estimate.