Question

Write each system of linear equations as an augmented matrix:

$$\begin{gathered} \left(a\right)\left\{\begin{array}{l}11x=-9y-5\\ 7x+5y=-1\end{array}\right. \\ \left(b\right)\left\{\begin{array}{l}5x-3y+2z=-5\\ 2x-y-z=4\\ 3x-2y+2z=-7\end{array}\right. \end{gathered}$$

Short answer

Augmented matrix of given system of linear equations :

Part $\left(a\right)\left[\begin{array}{rrr}11& 9& -5\\ 7& 5& -1\end{array}\right]$

Part$\left(b\right)\left[\begin{array}{rrrr}5& -3& 2& -5\\ 2& -1& -1& 4\\ 3& -2& 2& -7\end{array}\right]$

Step-by-step solution

Part (a) Step 1. Given Information.

Given system of linear equations is :-

$\left(a\right)\left\{\begin{array}{l}11x=-9y-5\\ 7x+5y=-1\end{array}\right.$

Part (a) Step 2. Write the equations in Standard form.

The first equation is not in standard form.

We rewrite the first equation in standard form.

$11x=-9y-5$

$11x+9y=-5$

Part (a) Step 3. Write Augmented matrix.

We replace the first equation with its standard form.

In the augmented matrix, the first equation gives us the first row and the second equation gives us the second row.

The vertical line replaces the equal signs.

$\left\{\begin{array}{l}11x+9y=-5\\ 7x+5y=-1\end{array}\right.\left[\begin{array}{rrr}11& 9& -5\\ 7& 5& -1\end{array}\right]$

Part (b) Step 1. Given Information.

Given system of linear equations is :-

$\left(b\right)\left\{\begin{array}{l}5x-3y+2z=-5\\ 2x-y-z=4\\ 3x-2y+2z=-7\end{array}\right.$

Part (b) Step 2. Write the equations in Standard form.

All three equations are in standard form.

$\left\{\begin{array}{l}5x-3y+2z=-5\\ 2x-y-z=4\\ 3x-2y+2z=-7\end{array}\right.$

Part (b) Step 3. Write Augmented matrix. 

In the augmented matrix the first equation gives us the first row, the second equation gives us the second row, and the third equation gives us the third row.

The vertical line replaces the equal signs.

$\left\{\begin{array}{l}5x-3y+2z=-5\\ 2x-y-z=4\\ 3x-2y+2z=-7\end{array}\right.\left[\begin{array}{rrrr}5& -3& 2& -5\\ 2& -1& -1& 4\\ 3& -2& 2& -7\end{array}\right]$