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In the following exercise, solve the system of equations using Cramer’s rule

x+y-3z=-1y-z=0-x+2y=1

Short Answer

Expert verified

This system of equations has infinitely many solutions.

Step by step solution

01

Step 1. Given information  

The given system of equations is:

x+y-3z=-1y-z=0-x+2y=1

02

Step 2.  Evaluating the determinant D 

In determinant Dall the coefficients are taken.

So,

D=11-301-1-120D=1(0+2)-1(0-1)-3(0+1)D=2+1-3D=0

03

Step 3. Evaluating the determinant Dx

In determinant Dx, we take the constants in place of coefficients of

So,

Dx=-11-301-1120Dx=-1(0+2)-1(0+1)-3(0-1)Dx=-2-1+3Dx=0

04

Step 4.  Evaluating the determinant Dy

In the determinant Dy, we take the constant in place of coefficients of

So,

Dy=1-1-300-1-110Dy=1(0+1)+1(0-1)-3(0+0)Dy=1-1Dy=0

05

Step 5. Evaluating the determinant Dz

In the determinant Dz, we take the constant in place of coefficients of

So,

Dz=11-1010-121Dz=1(1-0)-(0-0)-1(0+1)Dz=0

We can see that and Dzare zero. So the system of equations is consistent and has infinitely many solutions.

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