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Solve each system of equations using a matrix.

2x+3y+z=12x+y+z=93x+4y+2z=20

Short Answer

Expert verified

The system of linear equations doesn't have any solution.

Step by step solution

01

Step 1. Given information.

Consider the given system of equations,

2x+3y+z=12x+y+z=93x+4y+2z=20

02

Step 2. Write in augmented form.

The augmented matrix for the given system of equations is

23112111934220

03

Step 3. Apply row operations.

Apply R12R1and R3-1R3,

1321260-1212334220

Apply R3-3×R1R3and -2×R2R2,

13212601-1-60-12122

Apply R3+12×R2R3,

13212601-1-6000-1

Apply R3-1R3,

13212601-1-60001

Now, the matrix is in row-echelon form.

04

Step 4. Write in system of equations.

Writing the corresponding system of equations,

x+32y+12z=6......(i)y-z=-6......(ii)0=1......(iii)

As equation (iii) is a false statement.

Therefore, it is not possible to solve and is an inconsistent system.

Hence, the system of linear equations has no solution.

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