Question

In example 4.28, we used elimination to solve the system of equations,

$$\begin{gathered} s+b=40,000 \\ 0.08s+0.03b=0.071(40,000) \end{gathered}$$

Could you have used substitution or elimination to solve this system? Why?

Short answer

The elimination method is most suitable method to solve the given system of equation as both equations are in standard form.

Step-by-step solution

Step 1. Given information

We are given a system of linear equation,

$$\begin{gathered} s+b=40,000 \\ 0.08s+0.03b=0.071(40,000) \end{gathered}$$

Step 2. Convenient way to solve the system of equations.

The elimination method is most convenient method to solve the system of equation as both equations are in standard form.