Question

In the following exercises, solve each linear equation.$-6+6\left(5-k\right)=15$

Short answer

The answer is$k=\frac{3}{2}$

Step-by-step solution

Step 1. Given information

The equation is $-6+6\left(5-k\right)=15$

Find value of k and check

Step 2. Calculation

Simplify the equation $-6+6\left(5-k\right)=15$

$-6+30-6k=15$

Combine like terms

$$\begin{gathered} -6+30-15=6k \\ 9=6k \end{gathered}$$

Divide by 6 on both sides

$$\begin{gathered} \frac{9}{6}=k \\ \frac{3}{2}=k \end{gathered}$$

Step 3. Check

Substitute $\frac{3}{2}=k$in the equation $-6+6\left(5-k\right)=15$

$$\begin{gathered} -6+6\left(5-\frac{3}{2}\right)=15 \\ -6+6\left(\frac{7}{2}\right)=15 \\ -6+21=15 \\ 15=15 \end{gathered}$$