Question

Write the first five terms of the sequence where the first term is 11 and the common difference is d = −8.

Short answer

The first five terms are 11, 3, −5, −13, and −21.

Step-by-step solution

Step 1. Given Information.

Consider the given information.

First-term is 11 and the common difference is$d=-8$.

Step 2. Find the first five terms.

Use the first term and add the common difference. Then add the common difference to that result to get the next term, and so on.

$a_1=11$

And,

$\begin{array}{rcl}{a}_2& =& 11-8\\ & =& 3\end{array}$

And,

$\begin{array}{rcl}{a}_3& =& 3-8\\ & =& -5\end{array}$

And,

role="math" localid="1645271203725" $\begin{array}{rcl}{a}_4& =& -5-8\\ & =& -13\end{array}$

And,

$\begin{array}{rcl}{a}_5& =& -13-8\\ & =& -21\end{array}$

Step 3. Conclusion.

The obtained result is 11, 3, -5, -13, -21.