Question

In the following exercise solve $\frac{t-3}{5}=\frac{t+2}{9}$

Short answer

The solution is$t=\frac{37}{4}$

Step-by-step solution

Step 1. Given information

$\frac{t-3}{5}=\frac{t+2}{9}$

Step 2. solve

Multiply both sides by LCD.

$$\begin{gathered} \left(5·9\right)\left(\frac{t-3}{5}\right)=\left(5·9\right)\left(\frac{t+2}{9}\right) \\ 9\left(t-3\right)=5\left(t+2\right) \\ 9t-27=5t+10 \\ 4t-37=0 \\ t=\frac{37}{4} \end{gathered}$$