Question

Solve quadratic equation$y^2+12y+36=32$using square root property

Short answer

The values of$y$are$-6-4\sqrt{2}$and$-6+4\sqrt{2}$

Step-by-step solution

Step 1. Given information

The quadratic equation$y^2+12y+36=32$

Step 2. Factor the perfect square trinomial

$\Rightarrow {\left(y+6\right)}^2=32$

Step 3. Use square root property

$\Rightarrow y+6=\pm 4\sqrt{2}$

$\Rightarrow y=-6\pm 4\sqrt{2}$

$\Rightarrow y=-6-4\sqrt{2}$and$y=-6+4\sqrt{2}$