Question

$\text{Find the sum:}\left(14y^2+6y-4\right)+\left(3y^2+8y+5\right)$

Short answer

The sum of the polynomials is$17y^2+14y+1$

Step-by-step solution

Step 1. Given information 

$\begin{array}{l}\text{Thegivenpolynomialexpressionis}\\ \left(14y^2+6y-4\right)+\left(3y^2+8y+5\right)\\ \text{Wehavetofindthesum.}\end{array}$

Step 2. Identify the like terms and rewrite the expression 

$\begin{array}{l}\text{Wehave}\left(14y^2+6y-4\right)+\left(3y^2+8y+5\right)\\ \text{Rewritewithouttheparentheses,rearrangingtogettheliketermstogether}\\ \Rightarrow \left(14y^2+6y-4\right)+\left(3y^2+8y+5\right)=\underset{¯}{14y^2}+\underset{¯}{\underset{¯}{6y}}-4+\underset{¯}{3y^2}+\underset{¯}{\underset{¯}{8y}}+5\\ =14y^2+3y^2+6y+8y-4+5\\ =\left(14+3\right)y^2+\left(6+8\right)y+1\\ =17y^2+14y+1\end{array}$