Question

Find the quotient$-63c^8{d}^3÷\left(7c^{12}{d}^2\right)$

Short answer

The quotient is$-\frac{9d}{c^4}$

Step-by-step solution

Step 1. Given information

$-63c^8{d}^3÷\left(7c^{12}{d}^2\right)$

Step 2. Divide the polynomial

Rewrite as a fraction.

$\frac{-63c^8{d}^3}{7c^{12}{d}^2}$

Use fraction multiplication

$\frac{-63}{7}·\frac{c^8}{c^{12}}·\frac{d^3}{d^2}$

Simplify and use the quotient property.

$\frac{-9}{1}·\frac{1}{c^4}·\frac{d}{1}$

Multiply

$-\frac{9d}{c^4}$