Question

Find the quotient$\left(-72a^7{b}^3\right)÷\left(8a^{12}{b}^4\right)$

Short answer

The quotient is$-\frac{9}{a^{5}b}$

Step-by-step solution

Step 1. Given information

$\left(-72a^7{b}^3\right)÷\left(8a^{12}{b}^4\right)$

Step 2. Divide the Polynomial

Rewrite the fraction.

$\frac{-72a^7{b}^3}{8a^{12}{b}^4}$

use fraction multiplication.

$\frac{-72}{8}·\frac{a^7}{a^{12}}·\frac{b^3}{b^4}$

Simplify and use the quotient property.

$-9·\frac{1}{a^5}·\frac{1}{b}$

Multiply

$-\frac{9}{a^{5}b}$