Question

In the following exercises, add the polynomials.

$\left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)$

Short answer

Hence,

$\left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)=7r^2-6rs-2s^2$

Step-by-step solution

Step 1. Given information

$\begin{array}{l}\text{Thegivenexpressionsis}\\ \left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)\\ \text{Wehavetofindthesumofthepolynomials.}\end{array}$

Step 2. Add the polynomials

$\begin{array}{l}\Rightarrow \left(2r^2-3rs-2s^2\right)+\left(5r^2-3rs\right)\\ =2r^2-3rs-2s^2+5r^2-3rs\left[\text{Rewritewithoutparentheses}\right]\\ =2r^2+5r^2-3rs-3rs-2s^2\left[\text{Combinetheliketerms}\right]\\ =7r^2-6rs-2s^2\left[\text{Simplify}\right]\end{array}$