Question

Divide each polynomial by the binomial.

$\left(64x^3-27\right)÷\left(4x-3\right)$

Short answer

The solution is$\left(16x^2+12x+9\right)$.

Step-by-step solution

Step 1. Given information 

Polynomial:$64x^3-27$

Binomial:$4x-3$

Step 2. Calculation 

Using long division -

$16x^2+12x+9$

localid="1645989206912" $4x-3\overline{)64x^3-27}$

$64x^3-48x^2$

localid="1645989303781" $\overline{48x^2-27}$

localid="1645989426696" $48x^2-36x$

localid="1645989446533" $\overline{36x-27}$

$36x-27$

$\overline{0}$