Question

$\left(48y^4-24y^3\right)÷\left(-8y^2\right)$

Short answer

$-6y^2+3y$

Step-by-step solution

Step 1

Rewrite the given expression as a fraction.

$=\frac{48y^4-24y^3}{-8y^2}$

Step 2

Divide every term by divisor and take care of sign.

.$=\frac{48y^4}{-8y^2}-\frac{24y^3}{-8y^2}$

Step 3

Simplify to obtain the final answer.

$=-6y^2+3y$