Question

$\left(63m^4-42m^3\right)÷\left(-7m^2\right)$

Short answer

$m^2+6m$

Step-by-step solution

Step 1

Rewrite the given expression as a fraction.

$=\frac{63m^4-42m^3}{-7m^2}$

Step 2

Divide every term by divisor and take care of sign.

.$=\frac{63m^4}{-7m^2}-\frac{42m^3}{-7m^2}$

Step 3

Simplify to obtain the final answer.

$=m^2+6m$