Question

Simplify${\left(\frac{k^{-2}{k}^8}{k^3}\right)}^2$

Short answer

Simplified expression is$k^6$

Step-by-step solution

Given information  

Simplify${\left(\frac{k^{-2}{k}^8}{k^3}\right)}^2$

Simplification

Here

$$\begin{gathered} {\left(\frac{k^{-2}{k}^8}{k^3}\right)}^2={\left(k^{-2+8-3}\right)}^2 \\ ={\left(k^3\right)}^2 \\ =k^{3\times 2} \\ =k^6 \end{gathered}$$