Question

Find the intercepts of the equation$3x-2y=12$.

Short answer

The intercepts of the given equation are (4,0) and (0,-6).

Step-by-step solution

Given information

The equation is given as$3x-2y=12$.

Find the intercepts on the abscissa

Apply the definition of the intercepts to find the required answer to the given problem.

• Substitute each $y$by 0 into the given equation and solve to find the intercepts of the given equation on the abscissa.

$\begin{array}{rcl}3x-2y& =& 12\\ 3x-2\left(0\right)& =& 12\\ 3x& =& 12\\ x& =& \frac{12}{3}\\ x& =& 4\end{array}$

Find the intercepts on the ordinate

Now substitute each $x$by 0 into the given equation and solve to find the intercepts on the ordinate.

$\begin{array}{rcl}3x-2y& =& 12\\ 3\left(0\right)-2y& =& 12\\ 0-2y& =& 12\\ -2y& =& 12\\ y& =& \frac{12}{-2}\\ y& =& -6\end{array}$