Question

Graph the line of equation $3x+y=5$using its slope and y-intercept.

Short answer

The slope of equation $3x+y=5$is $-3$and the y-intercept is $(0,5)$and the graph is plotted below:

Step-by-step solution

Step 1. Given information

The equation of line is$3x+y=5$.

Step 2. Identify the slope of equation 

The slope intercept form of an equation is $y=mx+b$where $m$is the slope and $(0,b)$is the y-intercept.

The given equation $3x+y=5$is converted into slope intercept form as:

$$\begin{gathered} 3x+y=5 \\ y=-3x+5;(y=mx+b) \end{gathered}$$

Hence the slope of equation is$-3$.

Step 3. Identify the y-intercept

The y-intercept of equation$y=-3x+5$is$(0,5)$.

Step 4. Graph the line of equation 3x+y=5.

The graph of equation is plotted using slope $-3$and y-intercept $(0,5)$as shown below: