Question

For the following exercises, evaluate each expression.

$3x^2-2xy+4y^2$whenlocalid="1644418506893" $x=-2,y=-3$

Short answer

The value of the given expression is$36.$

Step-by-step solution

Step 1. Given information

$3x^2-2xy+4y^2;x=-2,y=-3$

Step 2. Evaluate expression

$$\begin{gathered} 3x^2-2xy+4y^2=3{\left(-2\right)}^2-2\left(-2\right)\left(-3\right)+4{\left(-3\right)}^2\text{use}x=-2,y=-3 \\ =3\left(4\right)-2\left(6\right)+4\left(9\right) \\ =12-12+36 \\ =36 \end{gathered}$$

Hence, the value of the given expression is$36.$