Question

Simplify: -$\frac{6}{17}·\frac{11}{25}·\frac{17}{6}.$

Short answer

$\frac{6}{17}·\frac{11}{25}·\frac{17}{6}=\frac{11}{25}.$

Step-by-step solution

Given Information

Given that$\frac{6}{17}·\frac{11}{25}·\frac{17}{6}.$

Solution

The first and third terms are reciprocals, so use the Commutative Property of multiplication to re-order the factors.

$$\begin{gathered} \frac{6}{17}·\frac{11}{25}·\frac{17}{6}=\frac{6}{17}·\frac{17}{6}·\frac{11}{25} \\ \frac{6}{17}·\frac{11}{25}·\frac{17}{6}=1·\frac{11}{25} \\ \frac{6}{17}·\frac{11}{25}·\frac{17}{6}=\frac{11}{25}. \end{gathered}$$

Final Answer

Hence,$\frac{6}{17}·\frac{11}{25}·\frac{17}{6}=\frac{11}{25}.$