Question

In the following exercises, factor each trinomial of the form

$x^2+bx+c$

$-11-10x+x^2$

Short answer

The binomial factors of the equations are $(x+11)(x-1)$.

Step-by-step solution

Step 1. Given information and rewriting the equation in general from  

The given equation is

$-11-10x+x^2$

The general form is

$x^2-10x-11$

Step 2. Writing factors as two binomial with n. 

The factors should be written as two binomials with n as the first term.

$(n)(n)$

The product of the two numbers is 11,and their sum is 10. Because the third term sign is negative, the sum seems to be a difference.

$\left[\begin{array}{cc}\mathrm{Factors}& 11\\ & 1\\ \mathrm{Difference}& 10\end{array}\right]$

So form of binomial is $(x11)(x1)$.

Step 3. Finding factors  

The larger binomial second term is also positive because the second trinomial term is positive.

Because the third trinomial term is negative, the binomial signs are transposed.

The binomial factors are as follows:

$(x+11)(x-1)$

Step 4. Checking the factors  

$$\begin{gathered} \mathrm{Check}:\mathrm{Multiply}\mathrm{the}\mathrm{factors}. \\ (x+11)(x-1)=x²-x+11x-11\left[\mathrm{Multiply}\right] \\ =x²+10x-11\mathrm{True}[\mathrm{Group}\mathrm{the}\mathrm{like}\mathrm{terms}] \end{gathered}$$