Question

Factor$y^2-16y+63$$x^2-16x+63$

Short answer

The factored form is$(x-9)(x-7)$

Step-by-step solution

Given information

Given the polynomial,$y^2-16y+63$

Writing as parentheses 

The polynomial can be written as$(x)(x)$. Now creating the table

Factors of$63$	Sum of factors
$1,63$	$1+63=64$
$3,21$	$3+21=24$
$-9,-7$	$-9-7=-16$

Use m,nas last terms of factors and form the factored polynomial

Here

$$\begin{gathered} m,n=-9,-7 \\ m+n=-16 \\ m\times n=63 \end{gathered}$$

Substitute the values and form the factored polynomial 

The factored form is$(x-9)(x-7)$