Question

For the function $f\left(x\right)=x^2-8x+3$

(a) find $x$when$f\left(x\right)=-4$

(b) Find two points that lie on the graph of the function.

Short answer

The value of$x$is$1,7$and points lying on the graph is$(1,-4),(0,3)$

Step-by-step solution

Given information

Given the function$f\left(x\right)=x^2-8x+3$

Substitute, f(x)=-4 and calculate the value

Substituting the values, we get

$$\begin{gathered} -4=x^2-8x+3 \\ {x}^2-8x+7=0 \\ {x}^2-7x-x+7=0 \\ x(x-7)-1(x-7)=0 \\ (x-1)(x-7)=0 \\ x=1,7 \end{gathered}$$

Calculate the corresponding y values

The corresponding points that lie on the graph is $(1,-4),(0,3)$the graph of which is