Question

In the following exercises, use the properties of logarithms to evaluate.

(a)${\log }_{7}1$

(b)${\log }_{12}12$

Short answer

The solution is-
(a)$0$

(b)$1$

Step-by-step solution

Step 1. Solving for part (a)

We have ${\log }_{7}1$.

We will evaluate this using the property, ${\log }_{a}1=0$. So,

${\log }_{7}1=0$.

Step 2. Solving for part (b)

We have ${\log }_{12}12$.

We will evaluate this using the property, ${\log }_{a}a=1$. So,

${\log }_{12}12=1$.