Question

In the following exercises, solve the system of equations by using graphing.

$\begin{array}{rcl}& & \left\{\begin{array}{l}y=-4\\ x^2+y^2=16\end{array}\right.\end{array}$

Short answer

The solution of the system is$(0,-4)$.

Step-by-step solution

Step 1. given information

The given system of equations is$\begin{array}{rcl}& & \left\{\begin{array}{l}y=-4\\ x^2+y^2=16\end{array}\right.\end{array}$.

Step 2. Graph the Equations

• Plot the given equations on the same graph.

• The blue line represents the first equation and the red line represents the second equation of the system.

Step 3. Determine the point of intersection

• From the graph, it is observed that the point of intersection of both equations is $(0,-4)$.
• So, the solution of the system is$(0,-4)$.