Question

(a) Find the center and radius, then (b) graph the circle:$3x^2+3y^2=27$

Short answer

The center and the radius of the circle are $(0,0)$ and $3$respectively. The graph of this circle is:

Step-by-step solution

Part (a) Step 1. Given information.

The equation of the circle is $3x^2+3y^2=27$

We have to find radius and center.

Also, we have to graph this circle.

Part (a) Step 2. Compare with the standard form of a circle to find radius and center 

We have, $3x^2+3y^2=27$

Divide each side by $3$,

$x^2+y^2=9$

Compare with role="math" localid="1645266472741" ${(x-h)}^2+{(y-k)}^2=r^2$

We have $(h,k)=(0,0)$

and$r=3$

Part (b) Step 1. Graph the circle using radius and center 

The graph is: