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Find the order and degree of the following differential equations: (i) \(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{d} \mathrm{x}^{2}}=\left\\{1+\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{4}\right\\}^{\frac{5}{3}}\) (ii) \(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}+3\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{2}=\mathrm{x} \ell \mathrm{n} \frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\) (iii) \(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}=\mathrm{x} \ell \mathrm{n}\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)\) (iv) \(\left(\frac{d^{4} y}{d x^{4}}\right)^{3}+4\left(\frac{d y}{d x}\right)^{7}+6 y=5 \cos 3 x\).

Short Answer

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Based on the provided step-by-step solution, the question for students could be: Question: Determine the order and degree for the given differential equations: (i) $\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{d}\mathrm{x}^{2}}=\left\\{1+\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{4}\right\\}^{\frac{5}{3}}$ (ii) $\frac{\mathrm{d}^{2}\mathrm{y}}{\mathrm{dx}^{2}}+3\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{2}=\mathrm{x}\ell \mathrm{n} \frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}$ (iii) $\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}=\mathrm{x} \ell\mathrm{n}\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)$ (iv) $\left(\frac{d^{4} y}{d x^{4}}\right)^{3}+4\left(\frac{d y}{d x}\right)^{7}+6 y=5 \cos 3 x$ Answer: 1. Equation (i) : Order = 2, Degree = 1 2. Equation (ii) : Order = 2, Degree = 1 3. Equation (iii) : Order = 2, Degree = 1 4. Equation (iv) : Order = 4, Degree = 3

Step by step solution

01

Equation (i)

The original equation is $\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{d} \mathrm{x}^{2}}=\left\\{1+\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{4}\right\\}^{\frac{5}{3}}.$ The highest order derivative in the equation is the second derivative, so the order is 2. Now, the power of the second derivative is just 1. Thus, the degree in this case is 1 for the highest order derivative.
02

Equation (ii)

The original equation is $\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}+3\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)^{2}=\mathrm{x} \ell \mathrm{n} \frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}$. The highest order derivative is still the second derivative. Therefore, the order is 2. The power of the second derivative on both sides of the equation is 1 (Note: we ignore the ln function). So, the degree is 1.
03

Equation (iii)

The original equation is $\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}=\mathrm{x} \ell \mathrm{n}\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)$. The order is again determined by the second derivative, making the order 2. The power of the second derivative is 1. Therefore, the degree is 1.
04

Equation (iv)

The original equation is $\left(\frac{d^{4} y}{d x^{4}}\right)^{3}+4\left(\frac{d y}{d x}\right)^{7}+6 y=5 \cos 3 x$. In this case, the highest order derivative is the fourth derivative. This makes the order 4. The power of the fourth derivative is 3, so we have a degree of 3 for the highest order derivative. To summarize, the orders and degrees are as follows: 1. Equation (i) : Order = 2, Degree = 1 2. Equation (ii) : Order = 2, Degree = 1 3. Equation (iii) : Order = 2, Degree = 1 4. Equation (iv) : Order = 4, Degree = 3

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Most popular questions from this chapter

Show that the equation \(\frac{d y}{d x}=\frac{y}{x}\) subject to the initial condition \(\mathrm{y}(0)=0\) has an infinite number of solutions of the form \(\mathrm{y}=\mathrm{Cx}\). The same equation subject to the initial condition \(\mathrm{y}(0)=\mathrm{a} \neq 0\) has no solution.

Show that the tangents to all integral curves of the differential equation \(y^{\prime}+y \tan x=x \tan x+1\) at the points of intersection with the y-axis are parallel. Determine the angle at which the integral curves cut the \(\mathrm{y}\)-axis.

Find all solutions of \(y^{\prime}+y \cot x=2 \cos x\) on the interval \((0, \pi)\). Prove that exactly one of these is also a solution on \((-\infty, \infty)\)

Solve the differential equation \(\frac{x d x+y d y}{\sqrt{x^{2}+y^{2}}}=\frac{y d x-x d y}{x^{2}}\)

A body in a room at \(60^{\circ}\) cools from \(200^{\circ}\) to \(120^{\circ}\) in halfan hour. (a) Show that its tmperature after \(\mathrm{t}\) minutes is \(60+140 \mathrm{e}^{-\mathrm{lt}}\), where \(\mathrm{k}=(\ln 7-\ln 3) / 30\) (b) Show that the time \(t\) required to reach a temperature of \(\mathrm{T}\) degrees is given by the formula \(\mathrm{t}=[\ln 140-\ln (\mathrm{T}-60)] / \mathrm{k}\), where \(60<\mathrm{T} \leq 200\). (c) Find the time at which the temperature is \(90^{\circ}\). (d) Find a formula for the temperature of the body at time \(t\) if the room temperature is not kept constant but falls at a rate of \(1^{\circ}\) each ten minutes. Assume the room temperature is \(60^{\circ}\) when the body temperature is \(200^{\circ}\).

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