Chapter 5: Problem 117
In the nth row of the triangle (a) last term \(=\) sum of the cubes of the first \(\mathrm{n}\) natural numbers (b) first term \(=\frac{\left(\mathrm{n}^{2}-\mathrm{n}+2\right)^{2}}{4}\) (c) positive square root of the first term is one more than the sum of first \(\mathrm{n}-1\) natural numbers (d) sum of the elements in the nth row \(=\frac{n\left(n^{2}+2\right)\left(3 n^{2}+1\right)}{12}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.