Chapter 3: Problem 59
\(\sin \left[\cot ^{-1}\left\\{\cos \left(\tan ^{-1} x\right)\right\\}\right]\) is (a) 1 (b) \(\sqrt{\frac{\mathrm{x}^{2}-1}{\mathrm{x}^{2}+2}}\) (c) \(\sqrt{\frac{x-2}{x^{2}+1}}\) (d) \(\sqrt{\frac{x^{2}+1}{x^{2}+2}}\)
Short Answer
Expert verified
Answer: (d) \(\sqrt{\frac{x^{2}+1}{x^{2}+2}}\)
Step by step solution
01
Find the value of \(\tan^{-1}(x)\)
We are given the expression \(\tan^{-1}(x)\). There is no direct simplification available for this expression, so we will leave it as it is.
02
Find the value of \(\cos(\tan^{-1}(x))\)
Let \(\alpha = \tan^{-1}(x)\). Then, \(\tan(\alpha) = x\). Using the identity \(\tan^2(\alpha) + 1 = \sec^2(\alpha)\) (where \(\sec(\alpha)\) is the reciprocal of \(\cos(\alpha)\)), we have:
\[x^{2} + 1 = \frac{1}{\cos^{2}(\alpha)}\]
So, we get the value of \(\cos(\alpha)\) (or \(\cos(\tan^{-1}(x))\)) as follows:
\[\cos(\tan^{-1}(x)) = \cos(\alpha) = \sqrt{\frac{1}{x^{2}+1}}\]
03
Find the value of \(\cot^{-1}\{\cos(\tan^{-1}(x))\}\)
Now, we need to find the value of \(\cot^{-1}(\cos(\tan^{-1}(x)))\). Let \(\beta = \cot^{-1}(\cos(\tan^{-1}(x)))\), so \(\cot(\beta)=\cos(\tan^{-1}(x))\). Then we have:
\[
\cot(\beta) = \sqrt{\frac{1}{x^{2}+1}}
\]
Sqaring both sides, we get:
\[
\cot^2(\beta) = \frac{1}{x^{2}+1}
\]
Using identity \(\cot^2(\beta)+1=\csc^2(\beta)\) (where \(\csc(\beta)\) is the reciprocal of \(\sin(\beta)\)), we have:
\[
\csc^2(\beta) = x^{2}+1+1
\]
So, we can find the value of \(\sin(\beta)\) (or \(\sin(\cot^{-1}(\cos(\tan^{-1}(x))))\)) as follows:
\[
\sin(\cot^{-1}(\cos(\tan^{-1}(x)))) = \sin(\beta) = \sqrt{\frac{1}{x^{2}+2}}
\]
04
Compare the expression with given options
At this point, we have found that:
\[
\sin(\cot^{-1}(\cos(\tan^{-1}(x)))) = \sqrt{\frac{1}{x^{2}+2}}
\]
Comparing this expression with the given options, we find that the answer is:
(d) \(\sqrt{\frac{x^{2}+1}{x^{2}+2}}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inverse Trigonometric Functions
Inverse trigonometric functions are the opposites of the basic trigonometric functions, allowing us to find the angle when given a ratio. For example, \(\tan^{-1}(x)\) gives us the angle whose tangent is \(x\). This is particularly useful when dealing with expressions or equations where the angle itself is the unknown.
Inverse functions are crucial in solving trigonometric equations because they help convert trigonometric ratios back into angles. These functions have specific domains and ranges, ensuring that they are properly defined. Here's a quick look at the range for some inverse trigonometric functions:
Inverse functions are crucial in solving trigonometric equations because they help convert trigonometric ratios back into angles. These functions have specific domains and ranges, ensuring that they are properly defined. Here's a quick look at the range for some inverse trigonometric functions:
- \(\sin^{-1}(x)\): Range is \([-\frac{\pi}{2}, \frac{\pi}{2}]\)
- \(\cos^{-1}(x)\): Range is \([0, \pi]\)
- \(\tan^{-1}(x)\): Range is \([-\frac{\pi}{2}, \frac{\pi}{2}]\)
Trigonometric Simplification
Trigonometric simplification involves transforming complex trigonometric expressions into simpler forms. This is often accomplished using known identities, such as Pythagorean identities, to make the expression easier to work with.
In the given exercise, simplification becomes critical when evaluating expressions like \(\cos(\tan^{-1}(x))\). We use the identity \(\tan^2(\alpha) + 1 = \sec^2(\alpha)\) to get:
In the given exercise, simplification becomes critical when evaluating expressions like \(\cos(\tan^{-1}(x))\). We use the identity \(\tan^2(\alpha) + 1 = \sec^2(\alpha)\) to get:
- From \(\tan(\alpha) = x\) and \(\sec^2(\alpha) = x^2 + 1\), we find \(\cos(\alpha) = \sqrt{\frac{1}{x^2 + 1}}\)
Analytic Trigonometry
Analytic trigonometry uses algebraic and geometric principles to solve problems involving trigonometric functions. It often involves arranging and manipulating expressions using known trigonometric identities and formulas.
Consider solving the problem \(\sin(\cot^{-1}(\cos(\tan^{-1}(x))))\), which involves progressing through several layers of trigonometric expressions. Each step uses a piece of analytic trigonometry to simplify and resolve these functions, aiming to match a given solution.
Consider solving the problem \(\sin(\cot^{-1}(\cos(\tan^{-1}(x))))\), which involves progressing through several layers of trigonometric expressions. Each step uses a piece of analytic trigonometry to simplify and resolve these functions, aiming to match a given solution.
- For instance, converting \(\cos(\tan^{-1}(x))\) to simpler terms through Pythagorean identity.
- Applying inverse trigonometric identities to find specific angle values.