Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Zeigen Sie, dass für eine zweimal stetig differenzierbare Lösung \(u(x, y)\) des Randwertproblems $$ -\Delta u=f \quad \text { in } \Omega, \quad u=0 \quad \operatorname{auf} \Gamma_{d}, \quad \frac{\partial u}{\partial \mathbf{n}}=q \quad \operatorname{auf} \Gamma_{n} $$ die Integralgleichung $$ \int_{\Omega}[\nabla u \cdot \nabla h-f h] d F-\int_{\Gamma_{n}} q h d s=0 $$ gilt, wobei \(f, q\) gegebene, integrierbare Funktionen sind und \(\Gamma=\Gamma_{d} \cup \Gamma_{n}, \Gamma_{d} \cap\) \(\Gamma_{n}=\emptyset\), der Rand von \(\Omega\) ist. \(h\) sei stetig differenzierbar und auf \(\Gamma_{d}\) gleich Null. \(\frac{\partial}{\partial \mathrm{n}}\) bezeichnet die Ableitung in Richtung der äußeren Normalen auf dem Rand \(\operatorname{von} \Omega\).

Short Answer

Expert verified
The integral equation holds due to the weak form derived from the PDE and boundary conditions.

Step by step solution

01

Understand the Problem Statement

We are given a boundary value problem involving the Laplacian \(-\Delta u = f\) in a region \(\Omega\) with boundary conditions: \(u = 0\) on \(\Gamma_d\), and \(\frac{\partial u}{\partial \mathbf{n}} = q\) on \(\Gamma_n\). We need to show that the given integral equation holds for a twice continuously differentiable solution \(u(x,y)\).
02

Set Up the Weak Form of the Problem

To derive the weak form, multiply the PDE by a test function \(h\), integrate over \(\Omega\), and apply integration by parts. The problem's weak form is: \[ \int_{\Omega} (-\Delta u) h \, dF = \int_{\Omega} f h \, dF. \]
03

Apply Integration by Parts

Using integration by parts, which states \(\int_{\Omega} \Delta u h \, dF = -\int_{\Omega} abla u \cdot abla h \, dF + \int_{\Gamma} \frac{\partial u}{\partial \mathbf{n}} h \, ds\), leads to: \[ -\int_{\Omega} abla u \cdot abla h \, dF + \int_{\Gamma} \frac{\partial u}{\partial \mathbf{n}} h \, ds = \int_{\Omega} f h \, dF. \]
04

Substitute Boundary Conditions

Substitute the boundary conditions into the integrated form. Use \(u = 0\) on \(\Gamma_d\) which implies \(h = 0\) on \(\Gamma_d\), and \(\frac{\partial u}{\partial \mathbf{n}} = q\) on \(\Gamma_n\) to get the expression: \[ -\int_{\Omega} abla u \cdot abla h \, dF + \int_{\Gamma_n} q h \, ds = \int_{\Omega} f h \, dF. \]
05

Conclusion of the Integral Equation

Rearrange the integrated form as initially stated: \[ \int_{\Omega} [abla u \cdot abla h - f h] \, dF - \int_{\Gamma_n} q h \, ds = 0. \] This shows that the integral equation holds given the boundary conditions and properties of \(u\) and \(h\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laplacian Operator
The Laplacian operator is a crucial component in mathematical physics and analysis. It is denoted as \( \Delta \) and often appears in boundary value problems, like the one we are tackling here. The Laplacian is a second-order differential operator given by the divergence of the gradient of a function. In two dimensions, for a function \( u(x, y) \), it is expressed as: \[\Delta u = \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2}.\]
  • The Laplacian operator measures how much the function \( u \) deviates from its mean value at a particular point.
  • It is widely used in physical problems where diffusion, wave propagation, or potential fields are involved.
  • In our boundary value problem, the condition \( -\Delta u = f \) signifies an equilibrium state, with \( f \) acting as a source term.
Understanding the Laplacian operator is vital, as it relates directly to the physical phenomena being modeled. Here, solving \( -\Delta u = f \) helps us deduce how \( u \) behaves under the specified conditions across the domain \( \Omega \).
Weak Formulation
Weak formulation is a modern mathematical approach to solving differential equations, particularly boundary value problems. Instead of focusing solely on the pointwise satisfaction of the differential equation, weak formulation emphasizes an average or integrated form of the equation over a domain.This concept involves introducing a test function, denoted \( h \), which belongs to a set of appropriately smooth functions. We multiply the original differential equation by \( h \) and integrate over the domain \( \Omega \). This transforms the problem into:\[\int_{\Omega} (-\Delta u)h \, dF = \int_{\Omega} f h \, dF.\]
  • This technique helps in deriving solutions that are smooth within \( \Omega \) but need not be differentiable everywhere.
  • It also accommodates more complex boundary conditions and irregular domains.
  • The test function \( h \) vanishes on the boundary \( \Gamma_d \), simplifying some terms in the process.
The weak formulation is particularly beneficial for numerical approximations, such as finite element methods, where exact solutions may be cumbersome or difficult to obtain analytically.
Integration by Parts
Integration by parts is an essential technique in calculus, especially when dealing with boundary value problems and converting differential equations into their weak forms.It facilitates the transformation of differential operators into boundary terms and simplified integrals. The integration by parts formula in the context of a boundary value problem is:\[\int_{\Omega} \Delta u h \, dF = -\int_{\Omega} abla u \cdot abla h \, dF + \int_{\Gamma} \frac{\partial u}{\partial \mathbf{n}} h \, ds.\]
  • This method essentially 'transfers' a derivative from one function to another within an integral.
  • When dealing with the Laplacian \( \Delta u \), integration by parts helps manage the terms involving gradients and divergence.
  • The boundary term \( \int_{\Gamma} \frac{\partial u}{\partial \mathbf{n}} h \, ds \) becomes key, since it connects the behavior of \( u \) at the boundary with the external conditions.
By applying integration by parts in our problem, we effectively reduce complexity, reconstituting our differential equation into an integral form which is easier to work with, especially when using test functions that fulfill specific boundary conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free