Question

Repeat Exercise 39 letting j be the horizontal line with equation $y=6$.

Short answer

a.

b.

c.

d.

Step-by-step solution

a.Step 1. Given Information.

The given line is $y=6$ and the point is $\left(4,3\right)$.

Step 2. Explanation.

Therefore, the graph is obtained as,

Step 3. Conclusion.

The graph is obtained with mirror image of the point $\left(4,3\right)$ at $\left(4,9\right)$.

b.Step 1. Given Information.

The given line is $y=6$ and the point is $\left(0,-2\right)$.

Step 2. Calculation.

Therefore, the graph is obtained as,

Step 3. Conclusion.

The graph is obtained with mirror image of the point $\left(0,-2\right)$ at $\left(0,14\right)$.

c.Step 1. Given Information.

The given line is $y=6$ and the point is $\left(-3,1\right)$.

Step 2. Calculation.

Therefore, the graph is obtained as,

Step 3. Conclusion.

The graph is obtained with mirror image of the point $\left(-3,1\right)$ at $\left(-3,11\right)$.

d.Step 1. Given Information.

The given line is $x=5$ and the point is $\left(x,y\right)$.

Step 2. Calculation.

Therefore, the graph is obtained as,

Step 3. Conclusion.

The graph is obtained with mirror image of the point $\left(x,y\right)$ at $\left(x,12-y\right)$.

Let us assume that $\left(x,y\right)$ is $\left(0,0\right)$ then the mirror image will be at $\left(0,12\right)$.