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For exercises, 14-18 write paragraph proofs.

Given: ABCD is a parallelogram; DE=BF.

Prove: AFCE is a parallelogram.

Short Answer

Expert verified

As, CFAEand AFCE, therefore AFCEis a parallelogram.

Step by step solution

01

Step 1. Observe the given diagram.

The given diagram is:

02

Step 2. Description of step.

As, DE=BF, therefore it can be noticed that:

DE=BFDE+EF=BF+EFDF=BE

Therefore, DFBE.

AsABCD is a parallelogram, therefore ABCD,ABCD and BD is a transversal.

From the given diagram it can be noticed that the angles FDCand EBA are the alternate interior angles.

Therefore, FDCEBA.

In the triangles DCFand BAE, it can be noticed that ABCD, FDCEBAand DFBE.

Therefore, the triangles DCFand BAEare congruent triangles by using the SAS postulate.

Therefore, by using the corresponding parts of congruent triangles it can be noticed that CFAE.

03

Step 3. Description of step.

AsABCD is a parallelogram, therefore ADCB,ADBC and BD is a transversal.

From the given diagram it can be noticed that the angles FDAand EBC are the alternate interior angles.

Therefore, FDAEBC.

In the triangles DAFand BCE, it can be noticed that ADCB, FDAEBCand DFBE.

Therefore, the triangles DAFand BCEare congruent triangles by using the SAS postulate.

Therefore, by using the corresponding parts of congruent triangles it can be noticed that AFCE.

04

Step 4. Description of step.

Therefore, it can be noticed that CFAEand AFCE.

Therefore, it can be said the pairs of opposite sides of the quadrilateral AFCE are congruent.

If the pairs of opposite sides of a quadrilateral are congruent then the quadrilateral is a parallelogram.

As, CFAEand AFCE, therefore AFCE is a parallelogram.

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