Question

What is

Short answer

$\begin{array}{r}{\mathrm{K}}_{\mathrm{sp}}=\left[{\mathrm{Ca}}^{+2}\right]\left[{\mathrm{SO}}_4^{-2}\right]\\ \left[{\mathrm{SO}}_4^{-2}\right]=\frac{2.4\times {10}^{-5}}{0.0005}\\ =0.048\mathrm{M}\end{array}$

$\begin{array}{r}\mathrm{Q}={\left[{\mathrm{Ag}}^{+}\right]}^2\left[{\mathrm{SO}}_4^{2-}\right]\\ =\left(0.0300{)}^2\right(0.048)\\ =4.3\times {10}^{-5}\end{array}$

$$\begin{gathered} {\mathrm{K}}_{\mathrm{sp}}={\left[{\mathrm{Ag}}^{+}\right]}^2\left[{\mathrm{SO}}_4^{-2}\right] \\ \left[{\mathrm{SO}}_4^2\right]=\frac{1.5\times {10}^{-5}}{(0.030{)}^2}=1.67\times {10}^2\mathrm{M} \\ {\mathrm{K}}_{\mathrm{sp}}=\left[{\mathrm{Ca}}^{+2}\right]\left[{\mathrm{SO}}_4^{-2}\right] \\ \left[{\mathrm{Ca}}^{2+}\right]=\frac{2.4\times {10}^{-5}}{1.67\times {10}^{-2}}=0.0014\mathrm{M} \end{gathered}$$

Step-by-step solution

Huyn

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