Question

Find the center and radius of each circle.

${\left(x-j\right)}^2+{\left(y+14\right)}^2=17$

Short answer

The center is (j, -14) and the radius is $\sqrt{17}$.

Step-by-step solution

Step-1 – Given

The given equation is ${\left(x-j\right)}^2+{\left(y+14\right)}^2=17$.

Step-2 – To determine

We have to find the center and the radius of the given circle.

Step-3 – Calculation 

We compare the given equation${\left(x-j\right)}^2+{\left(y+14\right)}^2=17$ with the standard form of a circle:${\left(x-a\right)}^2+{\left(y-b\right)}^2=r^2$.

Here (a, b) is the center and r being the radius.

Comparing the two equations we get: a = j, b = -14andr =$\sqrt{17}$ .

So, the center is (j, -14) and the radius is$\sqrt{17}$ .