Question

Find the center and radius of each circle.

${\left(x+3\right)}^2+y^2=49$

Short answer

The center is (-3, 0) and the radius is 7.

Step-by-step solution

Step-1 – Given

The given equation is ${\left(x+3\right)}^2+y^2=49$.

Step-2 – To determine

We have to find the center and the radius of the given circle.

Step-3 – Calculation 

We compare the given equation${\left(x+3\right)}^2+y^2=49$ with the standard form of a circle:${\left(x-a\right)}^2+{\left(y-b\right)}^2=r^2$.

Here (a, b) is the center and r being the radius.

Comparing the two equations we get: a = - 3, b = 0andr = 7.

So, the center is (-3, 0) and the radius is 7.