Question

On your paper, draw two segments roughly like those shown. Use these segments in Exercise $1-4$ to construct a segment having the indicated length. $3a-b$

Short answer

Draw $3a-b=$Three-times of length of line-segment $a-$ line-segment $b$.

Step-by-step solution

Step 1. Given information.

Two-line segments of lengths $a$ and $b$are given.

Step 2. Find the length.

Then, a segment of length $3a-b$ can be drawn by subtracting the length of the segment $b$from the segment $3a$.

The required length is,

$3a-b$

Step 3. Draw the line.

Now, Draw $3a-b$

Then $3a-b$will be as shown below,

Therefore, $3a-b=$Three-times of length of line-segment $a-$ line-segment $b$ as shown in the figure above.