Question

Construct an angle having the indicated measure.

$150$

Short answer

The figure is,

Step-by-step solution

Step 1. Given information.

The given angle is $150°$.

Step 2. Follow the ways.

Consider the line segment $AB$ and choose a point $C$on it.

$C\&B$as centre with radius role="math" localid="1648876761652" $BC$ draw two arcs.

Intersecting point is $D$.

$\angle DCB={60}^o$

$B\&D$as centre with radius$BC$ draw two arcs.

Intersecting point is $E$.

Here $EC$ is the bisector of $\angle BCD.$

$\angle BCE={30}^0$

Then

$\begin{array}{l}\angle ACE={150}^0\\ ={180}^0-\angle BCE.\end{array}$

Step 3. Construction.

The construction is shown below,

Therefore, the angle $150°$ is constructed.