Question

Given, $\Delta JKM$

Explain how to construct a triangle that is congruent to $\Delta JKM$.

Short answer

By $SSS$congruency, $\Delta JKM\cong \Delta PQR$.

Step-by-step solution

Step 1. Given information.

A triangle $\Delta JKM$ is given as shown below,

Step 2. Concept used.

According to $SSS$ congruence criteria,

if all the sides of one triangle are congruent to the corresponding sides of other triangle,

then the two triangles are said to be congruent.

Step 3. Construct a triangle.

Construct $\Delta PQR$such that,

$PQ\cong MJ, PR\cong MK, QR\cong JK$.

So,

$\Delta JKM\cong \Delta PQR$ (by $SSS$congruence criteria)

Therefore, by $SSS$congruency $\Delta JKM\cong \Delta PQR$.