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a. Draw a circle. Place points A,B, and C on it in such positions that

\[mAB+mBC\]does not equal

b. Does your example in part (a) contradict Postulate 16?

Short Answer

Expert verified

(a)The final answer is 50°and 310°.

(b)The final answer is NO.

Step by step solution

01

a.Step 1. Given information:

The given information is about the circle where mAB and mBC are the arcs of the circle.

02

Step 2. Concept used:

mAB means central angle of arc ABand mBCmeans central angle of arc BC. .

In the figure shown below, it is clear that mAB+mBC does not equal to mAC.

03

Step 3. Applying the concept:

mABmeans central angle of arc ABand mBCmeans central angle of arc BC..

In the figure shown below, it is clear that mAB+mBCdoes not equal to mAC.

Here,mAB=90+110=200

mBC=110mAC=90

04

b.Step 1. Given information:

The given information is about the circle where mAB and mBC are the arcs of the circle

05

Step 2. Concept used:

mABmeans central angle of arc ABand mBCmeans central angle of arc BC. .

In the figure shown below, it is clear that mAB+mBC does not equal to mAC.

06

Step 3. Applying the concept:

mABmeans central angle of arc ABand mBCmeans central angle of arc BC..

In the figure shown below, it is clear that mAB+mBCdoes not equal to mAC.

Here,mAB=90+110=200

mBC=110mAC=90

According to theorem,

mAC+mBC=mAB

It does not contradict the postulate, here points are interchanged.

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