Question

The diagonals of a rectangle are18cmlong and intersect at a$$" width="9" height="19" role="math">60∘angle. Find the area of the triangle.

Short answer

The area of the triangle is$81\sqrt{3}c{m}^2$ .

Step-by-step solution

Step 1. Given information.

The diagonal of a rectangle are18cm long and intersect at${60}^{\circ }$ angle.

Step 2. Concept  Used.

The area of the rectangle is
$A=length\times breadth$

Step 3. Let’s calculate the area of each square and the value of s.

The diagonal of a rectangle are18cm long.

i.e$AC=BD=18cm$

We know that the diagonals of a rectangle bisect each other.

Thus$\begin{array}{l}A=lb\\ A=\left(9\sqrt{3}\right)\left(9\right)\\ A=81\sqrt{3}c{m}^2\end{array}$