Question

Consecutive sides of the figures are perpendicular. Find the area of each figure.

Short answer

Area of the figure $\left(A\right)=49.4sq.units$

Step-by-step solution

Step 1. Given information.

Consecutive sides of the figure is perpendicular.

Step 2. Concept  Used.

Since the two triangles are right angles triangle.

Where, i is the base of the triangles ,b is the height of the triangles and H is the Hypotenuse of the triangles.

$\begin{array}{l}\mathrm{Sin}{26}^0=\frac{b}{10}\\ b=10\mathrm{Sin}{26}^0\\ \mathrm{Cos}{26}^0=\frac{l}{10}\\ l=10\mathrm{Cos}{26}^0\end{array}$

 Step 3. Let’s calculate the area of the figure. 

Now, area of the figure

$\begin{array}{c}A=(b\times l)\\ =\left(10\sin {26}^0\right)\times \left(10\cos {26}^0\right)\\ =\left(49.4\right)sq.units\end{array}$

Therefore, the area of the figure $\left(A\right)=49.4sq.units$