Chapter 2: Problem 91
Symmetries of the cube. The intersection point of the diagonals is the center of symmetry of the cube (Figure 78). There are nine planes of symmetry: 6 diagonal planes (such as \(\mathrm{D} B F H\) ) and three planes passing through the midpoints of each quadruple of parallel edges. The cube has nine axes of symmetry of the 2nd order: six lines connecting the midpoints of opposite edges (e.g. of \(A D\) and \(F G\) ), and three lines connecting the centers of each pair of the opposite faces. The latter lines are in fact axes of symmetry of the 4 th order. In addition, the cube has four axes of symmetry of the 3rd order, namely its diagonals (e.g. \(A G\) ). Indeed, the diagonal \(A G\), obviously, makes congruent angles with the edges \(A B, A D\), and \(A E\), and these angles make the same (right) angles with each other. If we connect the points \(B, D\), and \(E\), then we obtain a regular triangular pyramid, \(A B D E\), for which the diagonal \(A G\) is the altitude. When the cube is rotated about this diagonal through the angle of \(120^{\circ}\), the pyramid returns to its original position. The same is true about the pyramid \(G H F C\), centrally symmetric to the pyramid \(A B D E\). Thus, as the
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