Chapter 2: Problem 9
Lateral surface area of prisms. Theorem. The lateral surface area of a prism is equal to the product of a lateral edge and the perimeter of a perpendicular cross section. By a perpendicular cross section (Figure 51) of a prism, we mean the polygon abcde obtained by intersecting all lateral faces of the prism by a plane perpendicular to the lateral edges. Sides of this polygon are perpendicular to the lateral edges \((\S \S 31,20)\). The lateral surface area of the prism is equal to the sum of areas of parallelograms. In each of them, a lateral edge can be considered as the base, and one of the sides of the perpendicular cross section as the altitude. Therefore the lateral surface area is equal to \(A A^{\prime} \cdot a b+\) \(B B^{\prime}+b c+C C^{\prime} \cdot c d+D D^{\prime} \cdot d e+E E^{\prime} \cdot e a=A A^{\prime} \cdot(a b+b c+c d+d e+e a)\). Corollary. The lateral surface area of a right prism is equal to the product of the perimeter of the base and the altitude, because lateral edges of such a prism are congruent to the altitude, and its base can be considered as the perpendicular cross section.
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