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find a differential operator that annihilates the given function

x2ex-xsin4x+x3

Short Answer

Expert verified

D4(D-1)3D2+162is the differential operator that annihilates the given function.

Step by step solution

01

Any nonhomogeneous term of the form f(x)=xkeαxcosβx OR role="math" localid="1663946799201" xkeαxsinβxsatisfiesrole="math" localid="1663946761280" (D-α)2+β2m[f]=0for K=0,1,2,...,m-1

Let the function bef(x)=x2ex-xsin4x+x3

Letg(x)=x2ex

Then

(D-1)3[g]=0

Leth(x)=xe-5xsin3x

Then

D2+422[h]=0

Leti(x)=x3

Then

D4[i]=0

Hence

(D-1)3D2+162D4[f]=0D4(D-1)3D2+162[f]=0

ThenD4(D-1)3D2+162 is the differential operator that annihilates the given function.

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Most popular questions from this chapter

Reduction of Order. If a nontrivial solution f(x) is known for the homogeneous equation

,y(n)+p1(x)y(n-1)+...+pn(x)y=0

the substitutiony(x)=v(x)f(x)can be used to reduce the order of the equation for second-order equations. By completing the following steps, demonstrate the method for the third-order equation

(35)y'''-2y''-5y'+6y=0

given thatf(x)=ex is a solution.

(a) Sety(x)=v(x)exand compute y′, y″, and y‴.

(b) Substitute your expressions from (a) into (35) to obtain a second-order equation in.w=v'

(c) Solve the second-order equation in part (b) for w and integrate to find v. Determine two linearly independent choices for v, say, v1and v2.

(d) By part (c), the functions y1(x)=v1(x)exand y2(x)=v2(x)exare two solutions to (35). Verify that the three solutions ex,y1(x), and y2(x)are linearly independent on(-,)

Find a general solution to the givenhomogeneous equation.(D+1)2(D6)3(D+5)(D2+1)(D2+4)2[y]=0

. find a differential operator that annihilates the given function.

xe-2x+xe-5xsin3x

As an alternative proof that the functions er1x,er2x,er3x,...,ernxare linearly independent on (∞,-∞) when r1,r2,...rn are distinct, assume C1er1x+C2er2x+C3er3x+...+Cnernxholds for all x in (∞,-∞) and proceed as follows:

(a) Because the ri’s are distinct we can (if necessary)relabel them so that r1>r2>r3>...>rn.Divide equation (33) by to obtain C1+C2er2xer2x+C3er3xer3x+...+Cnernxernx=0Now let x→∞ on the left-hand side to obtainC1 = 0.(b) Since C1 = 0, equation (33) becomes

C2er2x+C3er3x+...+Cnernx= 0for all x in(∞,-∞). Divide this equation byer2x

and let x→∞ to conclude that C2 = 0.

(c) Continuing in the manner of (b), argue that all thecoefficients, C1, C2, . . . ,Cn are zero and hence er1x,er2x,er3x,...,ernxare linearly independent on(∞,-∞).

Determine whether the given functions are linearly dependent or linearly independent on the specified interval. Justify your decisions.

{e3x,e5x,e-x}on(-,)

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